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Q. The ratio of voltage sensitivity ( $V_{S}$ ) and current sensitivity ( $I_{s}$ ) of a moving coil galvanometer is

NTA AbhyasNTA Abhyas 2020Current Electricity

Solution:

Voltage sensitivity $=\frac{Q}{V}$
Current sensitivity $=\frac{Q}{I}$
Also, potential difference
$V=IG$
Hence,
$\therefore \frac{V_{s}}{I_{s}}=\frac{1}{G}$