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Q. The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration $ a $ is $3 : 2$ The value of $ a $ is
($g =$ acceleration due to gravity of the earth)

Chhattisgarh PMTChhattisgarh PMT 2005

Solution:

According to the question
$\frac{W_{1}}{W_{2}}=\frac{m g}{m(g-a)}=\frac{3}{2}$
or $\frac{g}{g-a}=\frac{3}{2}$
$\Rightarrow a=\frac{g}{3} \,m / s^{2}$