Q. The ratio of the volume of a tetragonal lattice unit cell to that of a hexagonal lattice unit cell is(both having same respective lengths)
The Solid State
Solution:
Ratio $=\frac{a b c}{6 \times\left(\frac{\sqrt{3}}{4} a^2\right) \times c}=\frac{2}{3 \sqrt{3}}$
Note: $\frac{c}{a}=\frac{2 \sqrt{2}}{\sqrt{3}}$ for an ideal hcp
[Refer section $1.22(f$ and $g )]$
