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Q. The ratio of the speed of the electron in the first Bohr orbit of hydrogen and the speed of light is equal to (where $e, h$, and $c$ have their usual meanings in cgs system)

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Solution:

$v_{n}=k \frac{2 \pi e^{2}}{n h}$
We know that in cgs system $k=1$
$\therefore v_{n}=\frac{2 \pi e^{2}}{n h} $
$\Rightarrow v_{1}=\frac{2 \pi e^{2}}{h}$
So $\frac{v_{1}}{c}=\frac{2 \pi e^{2}}{c h}$