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  4. The ratio of the number of moles of AgNO3, Pb(NO3)2 and Fe(NO3)3 required for coagulation of a definite amount of a colloidal sol of silver iodide prepared by mixing AgNO3 with excess of KI will be

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Q. The ratio of the number of moles of $AgNO_3$, $Pb(NO_3)_2$ and $Fe(NO_3)_3$ required for coagulation of a definite amount of a colloidal sol of silver iodide prepared by mixing $AgNO_3$ with excess of $KI$ will be

Surface Chemistry

Solution:

With excess of $KI$, colloidal particles will be $[AgI]I^-$
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$\therefore \quad$ Molar ratio required for coagulation of same amount of $\left[AgI\right]I^{-}$ is $= 1 : \frac{1}{2} : \frac{1}{3} = 6 : 3 : 2$