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Q.
The ratio of the heat capacities $C_p /C_V$ for one mole of a gas is $1.67$. The gas is
KVPYKVPY 2009
Solution:
The ratio of molar heat capacities at constant pressure to that at constant volume is represented by $\gamma$ .
The value of $\gamma$ gives information about the atomicity of
gases.
If$\frac{C_{p}}{C_{V}}=1.67,$ gas will be monoatomic.
If$\frac{C_{p}}{C_{V}}=1.40,$ gas will be diatomic.
If$\frac{C_{p}}{C_{V}}=1.33,$ gas will be triatomic.
As given in question, $C_p/C_V$ for one mole of a gas is $1.67. i.e$.
$\frac{C_{p}}{C_{V}}=\gamma=1.67$
$\therefore $ It will be a monoatomic gas.
Thus, from the given options,
He is a monoatomic
gas.