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  4. The ratio of the energy of the electron in the ground state of hydrogen to the electron in first excited state of Be3+ is

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Q. The ratio of the energy of the electron in the ground state of hydrogen to the electron in first excited state of $Be^{3+}$ is

Structure of Atom

Solution:

(1) $\rightarrow H \quad(2) \rightarrow Be ^{3+}$

$\frac{E_{1}}{E_{2}}=\frac{Z_{1}^{2}}{n_{1}^{2}} \times \frac{n_{2}^{2}}{Z_{2}^{2}}$

$ \Rightarrow \frac{1}{1} \times \frac{4}{16}=\frac{1}{4}$