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Q. The ratio of the energy of photon of $2000 \mathring{A}$ wavelength radiation to that of $4000$ A radiation is

Structure of Atom

Solution:

$E=h v$ and $\Delta E=\frac{h c}{\lambda}$
$\frac{E_1}{E_2}=\frac{\lambda_2}{\lambda_1}=\frac{4000}{2000}=2$