Question

The ratio of the binding energy of a satellite at rest on earth's surface to the binding energy of a satellite of same mass revolving around the earth at a height $h$ above the earth's surface is $\left(\right.R$ = radius of the earth

• A. $\frac{2 \left(\right. R + h \left.\right)}{R}$
• B. $ \, \frac{R + h}{2 R}$
• C. $\frac{R + h}{R}$
• D. $\frac{R}{R + h}$

Answer 1

Answer: (C)

Binding energy on the surface of the earth
$E_{1}=\frac{G M m}{2 R}$
Binding energy of revolving satellite
$E_{2}=\frac{G M m}{2 \left(\right. R + h \left.\right)}$
$\therefore \, \frac{E_{1}}{E_{2}}=\frac{\left(\right. R + h \left.\right)}{R} \, $