Question

The ratio of the adiabatic bulk modulus to the isothermal bulk modulus of a perfect gas is equal to (symbols have their usual meanings)

• A. $ {{C}_{p}}-{{C}_{V}} $
• B. $ \frac{{{C}_{P}}}{{{C}_{V}}} $
• C. $ \frac{{{C}_{V}}}{{{C}_{P}}} $
• D. $ \sqrt{\frac{{{C}_{P}}}{{{C}_{V}}}} $

Answer 1

Answer: (B)

Adiabatic bulk modulus $ ={{B}_{adia}}=\gamma P $ Isothermal bulk modulus $ ={{B}_{iso}}=P $ $ \Rightarrow $ $ \frac{{{B}_{adia}}}{{{B}_{iso}}}=\gamma =\frac{{{C}_{P}}}{{{C}_{V}}} $