Question

The ratio of the adiabatic bulk modulus to the isothermal bulk modulus of a perfect gas is equal to (symbols have their usual meanings)

• A. $ C_{p}-C_{v} $
• B. $ \frac{C_{p}}{C_{v}} $
• C. $ \frac{C_{v}}{C_{p}} $
• D. $ \sqrt{\frac{C_{p}}{C_{v}}} $

Answer 1

Answer: (B)

Adiabatic bulk modulus $=B_{\text{adia}}=\gamma p$
Isothermal bulk modulus $=B_{\text {iso }}=p$
$\Rightarrow \frac{B_{\text {adia }}}{B_{\text {iso }}}=\gamma=\frac{C_{p}}{C_{V}}$