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Q. The ratio of specific charge of an $ \text{-} $ particle to that of a proton is

Rajasthan PMTRajasthan PMT 2003Atoms

Solution:

Rate of specific charge
$=\frac{(q / m)_{\alpha}}{(q / m)_{p}}=\frac{\left(2 e / 4 m_{p}\right)}{e / m_{p}}=\frac{1}{2}$