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Q. The ratio of resolving power of telescope, when lights of wavelength $4400 \,\mathring{A}$ and $5500\,\mathring{A}$ are used, is _______

Gujarat CETGujarat CET 2019

Solution:

Resolving power $\propto \frac{1}{\lambda}$
$\frac{\theta_{1}}{\theta_{2}}=\frac{\lambda_{2}}{\lambda_{1}}=\frac{5500}{4400}=\frac{5}{4}$