Question

The ratio of kinetic energy and the total energy of the electron in the $n^{th}$ quantum state of Bohr's atomic model of a hydrogen atom is

• A. $-2$
• B. $-1$
• C. $2$
• D. $1$

Answer 1

Answer: (B)

The Kinetic energy of the electron in the $n^{th}$ state
$ \, K=\frac{m Z^{2} e^{4}}{8 \epsilon _{0}^{2} h^{2} n^{2}}$
The total energy of the electron in the $n^{th}$ state
$ \, T \, = \, -\frac{m Z^{2} e^{4}}{8 \epsilon _{0}^{2} h^{2} n^{2}}$
$\therefore \, \, \, \frac{K}{T}= \, -1$