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  4. The ratio of ionization energy of Bohr's hydrogen atom and Bohr's hydrogen like lithium atom is

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Q. The ratio of ionization energy of Bohr's hydrogen atom and Bohr's hydrogen like lithium atom is

Atoms

Solution:

Energy of an electron in the ground state of an atom (Bohr's hydrogen like atom) is given as
$E =-13.6 Z ^{2} eV$
$(Z=$ atomic number of the atom
$\Rightarrow E_{\text {ionisation }}=13.6 Z ^{2}$
$\Rightarrow \frac{( E )_{ H }}{\left( E _{ ion }\right)_{ Li }}=\left(\frac{ Z _{ H }}{ Z _{ Li }}\right)^{2}=\left(\frac{1}{3}\right)^{2}=\frac{1}{9}$