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Q.
The ratio of intensities in consecutive maxima in a diffraction pattern due to a single slit is
NTA AbhyasNTA Abhyas 2020Wave Optics
Solution:
$I=I_{0}\left(\frac{sin \left(\alpha \right)}{\alpha }\right)^{2}$ and $\alpha =0,\frac{3 \pi }{2},\frac{5 \pi }{2}, \, \ldots \ldots \ldots $ , for maxima
The ratio of Intensities of successive maxima is
$1:\left(\frac{2}{3 \pi }\right)^{2}:\left(\frac{2}{5 \pi }\right)^{2}$ or $1:\frac{4}{9 \pi ^{2}}:\frac{4}{25 \pi ^{2}}$