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Q. The ratio of close-packed atoms to tetrahedral holes in cubic close packing is

The Solid State

Solution:

Every constituent has two tetrahedral voids. In ccp lattice atoms
$=8 \times \frac{1}{8}+6 \times \frac{1}{2}=4$
$\therefore $ Tetrahedral void $=4 \times 2=8$,
Thus, ratio $=4: 8:: 1: 2$.