Question

The ratio of average speed of an oxygen molecule to the rms speed of a nitrogen molecule at the same temperature is :

• A. $\left(\frac{3 \pi }{7}\right)^{1 / 2}$
• B. $\left(\frac{7}{3 \pi }\right)^{1 / 2}$
• C. $\left(\frac{3}{7 \pi }\right)^{\sqrt{2}}$
• D. $\left(\frac{7 \pi }{3}\right)^{1 / 2}$

Answer 1

Answer: (B)

$\frac{\bar{V}}{V_{rms}}=\sqrt{\frac{8 \times M_{v 2}}{3 \left(\pi M\right)_{O_{2}}}}=\sqrt{\frac{8 \times 28}{3 \pi \times 32}}=\left(\frac{7}{3 \pi }\right)^{v_{2}}$