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Q. The ratio of average electric energy density and total average energy density of electromagnetic wave is:

JEE MainJEE Main 2023Electromagnetic Waves

Solution:

$< u _{ E }>=< u _{ B }>=\frac{1}{2}< u _{\text {total }}>$
So $\frac{\left\langle u _{ E }\right\rangle}{\left\langle u _{\text {total }}\right\rangle}=\frac{1}{2}$