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Q. The rate of a reaction quadruples when the temperature changes from $300$ to $310\, K$. The activation energy of this reaction is :
(Assume activation energy and pre-exponential factor are independent of temperature; $ln\, 2 = 0.693; R=8.314 \,J$ $mol^{-1} \, K^{-1}$)

JEE MainJEE Main 2017Chemical Kinetics

Solution:

$4=e^{\frac{Ea}{R}\left\{\frac{1}{300}-\frac{1}{310}\right\}}$

In$\left(4\right)=\frac{Ea}{R}\left\{\frac{10}{300\times310}\right\}$

$Ea=\frac{0.693\times 2\times 8.314\times 300\times 310}{10}$

$=107165.79 \,J =107.165\, KJ$