Question

The rate law for the chemical reaction

$2\text{N}\text{O}_{2}\text{C} \text{l} \rightarrow 2\text{N}\text{O}_{2}+\text{C}\text{l}_{2}$ $= \text{k} \left[\text{N} \text{O}_{2} \text{Cl}\right]$ is rate The rate determining step is

• A. $2\text{N}\text{O}_{2}\text{C}\text{l} \rightarrow 2\text{N}\text{O}_{2}+2\text{C}\text{l} \, $
• B. $\text{N}\text{O}_{2}+\text{C}\text{l}_{2} \rightarrow \text{N}\text{O}_{2}\text{C}\text{l}+\text{C}\text{l}$
• C. $\text{N}\text{O}_{2}\text{C}\text{l}+\text{C}\text{l} \rightarrow \text{N}\text{O}_{2}+\text{C}\text{l}_{2}$
• D. $\text{N}\text{O}_{2}\text{C}\text{l} \rightarrow \text{N}\text{O}_{2}+\text{C}\text{l}$

Answer 1

Answer: (D)

Rate = $\text{k}\left[\right.\text{N} \text{O}_{2}\text{C}\text{l}\left]\right.$

Hence ,rate determtextning step is

$\text{N} \text{O}_{2}\text{C}\text{l} \rightarrow \text{N} \text{O}_{2}+\text{C}\text{l}$