Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The rate expression for the reaction,
$A_{(g)}+B_{(g)} \longrightarrow C_{(g)}$, is rate $=k[A]^{2}[B]^{1 / 2}$
What changes in the initial concentrations of $A$ and $B$ will cause the rate of reaction to increase by a factor of eight?

Chemical Kinetics

Solution:

If $\left[A^{\prime}\right]=2[A], \quad\left[B^{\prime}\right]=4[B]$

Rate $=k\left[A^{\prime}\right]^{2}\left[B^{\prime}\right]^{1 / 2}=k[2 A]^{2}[4 B]^{1 / 2}=k[A]^{2}[B]^{1 / 2} \times 8$