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Q. The rate constant of a reaction is $1.5 \times 10^{7} \,s ^{-1}$ at $50^{\circ} C$ and $4.5 \times 10^{7} \,s ^{-1}$ at $100^{\circ} C$. What is the value of activation energy?

Chemical Kinetics

Solution:

$\log \frac{4.5 \times 10^{7}}{1.5 \times 10^{7}}=\frac{E_{a}}{2.303 \times 8.314}\left[\frac{373-323}{373 \times 323}\right]$
$T _{1}=50+273=323$
$T _{2}=100+273=373$
$\log 3=\frac{E_{a}}{2.303 \times 8.314}\left[\frac{50}{373 \times 323}\right]$
$\frac{0.4770 \times 2.303 \times 8.314 \times 373 \times 323}{50}=E_{a}$
$E_{a}=22007\, J \,mol ^{-1} \approx 2.2 \times 10^{4}$