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Q. The rate constant of a reaction is $0.69\times 10^{- 1}min^{- 1}$ and the initial concentration is $0.2molL^{- 1}$ . The half life period is :-

NTA AbhyasNTA Abhyas 2020

Solution:

$\frac{t_{1}}{2}=\frac{0 . 693}{K}$
$\frac{t_{1}}{2}=\frac{0 . 693}{0 . 69 \times 10^{- 1}}=10min$
$t_{\frac{1}{2}}=10\times 60sec\Rightarrow 600sec$