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Q. The rate constant of a first order reaction is doubled when the temperature is increased from $20^{\circ}\, C$ to $25^{\circ}\, C$. How many times the rate constant will increase if the temperature is raised from $20^{\circ}\, C$ to $40^{\circ}\, C$ ?

KEAMKEAM 2012Chemical Kinetics

Solution:

For every $5^{\circ}$ rise in temperature, the rate constant becomes double.

$\therefore $ For $20^{\circ} C (5 \times 4$ times $)$ rise in temperature, the rate constant, $k=2^{4}=16$.