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Q. The rate constant of a first order reaction is $15\times10^{-3} s^{-1}\cdot$ How long will $5.0\, g$ of this reactant take to reduce to $3.0 \,g$?

Chemical Kinetics

Solution:

$t=\frac{2.303}{k} log \frac{a}{\left(a-x\right)}$
or $\quad$ $ t=\frac{2.303}{15\times10^{-3}} log$ $ \frac{5}{3}=34.07 \,s$