1. Tardigrade
  2. Question
  3. Chemistry
  4. The rate constant for the forward and backward reactions of hydrolysis of ester are 1.1 × 10-2 and 1.5 × 10-3 min -1 respectively. The equilibrium constant of the reaction is

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Q. The rate constant for the forward and backward reactions of hydrolysis of ester are $1.1 \times 10^{-2}$ and $1.5 \times 10^{-3} \min ^{-1}$ respectively. The equilibrium constant of the reaction is

Chemical Kinetics

Solution:

$K =\frac{ K _{\text {forward }}}{ K _{\text {backward }}}=\frac{1.1 \times 10^{-2}}{1.5 \times 10^{-3}}=7.33$