1. Tardigrade
  2. Question
  3. Chemistry
  4. The rate constant for forward reaction and backward reaction of hydrolysis of ester are 1.1 × 10-2 and 1.5 × 10-3 per minute respectively. Equilibrium constant for the reaction is CH 3 COOC 2 H 5+ H 2 O leftharpoons CH 3 COOH + C 2 H 5 OH

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The rate constant for forward reaction and backward reaction of hydrolysis of ester are $1.1 \times 10^{-2}$ and $1.5 \times 10^{-3}$ per minute respectively.
Equilibrium constant for the reaction is
$CH _{3} COOC _{2} H _{5}+ H _{2} O \rightleftharpoons CH _{3} COOH + C _{2} H _{5} OH$

VITEEEVITEEE 2014

Solution:

$k_{f}=1.1 \times 10^{-2}, k_{b}=1.5 \times 10^{-3}$
$K_{c}=\frac{k_{f}}{k_{b}}=\frac{1.1 \times 10^{-2}}{1.5 \times 10^{-3}}=7.33$