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Q.
The range of voltmeter of resistance $300 \Omega$ is $5 V$. The resistance to be connected to convert it into an'ammeter of range $5 A$ is
Moving Charges and Magnetism
Solution:
A voltmeter is a galvanometer having a high resistance connected in series with it. The current through the galvanometer
is $I_{g}=\frac{5 V }{300 \Omega}=\frac{1}{60} A$
An ammeter is a galvanometer having a low resistance connected in parallel with it. The shunt resistance $S$ is determined from
$\frac{I_{g}}{I-I_{g}}=\frac{S}{G}$
where $G=300 \Omega$ (Given)
For $I=5 A$, we get,
$\frac{1 / 60}{5-(1 / 60)}=\frac{S}{300} $
$\Rightarrow S=1 \Omega$