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Q. The range of the function
$f(x) = \frac{cosec^{-1} x + cos^{-1} (1/x)}{cosec\,x} $ is

Inverse Trigonometric Functions

Solution:

$f(x) = \frac{cosec^{-1} x + sec^{-1} x}{cosec\,x} , cos^{-1}(1/x) = sec^{-1} x $
$f(x) = \frac{\pi}{2} sin \,x$
Now, $-1 \le sin\,x \le 1$
$\therefore -\frac{\pi}{2} \le \frac{\pi}{2} \,sin\,x \le \frac{\pi}{2}$
$\Rightarrow - \frac{\pi}{2} \le f(x) \le \frac{\pi}{2}$