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Q.
The range of f(x)=cot−1(−x)−tan−1x+sec−1x is
Inverse Trigonometric Functions
Solution:
We have f(x)=π−cot−1x−tan−1x+sec−1x=π−π2+sec−1x=π2+sec−1x
As domain of f(x) is (−∞,−1]∪[1,∞)( As cot−1(−x)=π−cot−1x) ∴ Range of f(x) is [π2,π)∪(π,3π2].