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Q. The range of f(x)=cot1(x)tan1x+sec1x is

Inverse Trigonometric Functions

Solution:

We have f(x)=πcot1xtan1x+sec1x=ππ2+sec1x=π2+sec1x
As domain of f(x) is (,1][1,) ( As cot1(x)=πcot1x)
Range of f(x) is [π2,π)(π,3π2].