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  4. The radius of the second Bohr orbit, in terms of the Bohr radius, a0, in Li2+ is :

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Q. The radius of the second Bohr orbit, in terms of the Bohr radius, $a_0,$ in $Li^{2+}$ is :

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Solution:

$r_{n}=\frac{n^{2}\times a_{0}}{z}$
For $2^{nd}$ Bohr orbit of $Li^{+2}$
$n=2$
$z=3$
$\Rightarrow r_{n}=\frac{2^{2}\times a_{0}}{3}=\frac{4a_{0}}{3}$