1. Tardigrade
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  3. Chemistry
  4. The radius of the 4 text th Bohr's orbit is 0.864 nm. The de Broglie wavelength of the electron in that orbit is:

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Q. The radius of the $4^{\text {th }}$ Bohr's orbit is $0.864\, nm$. The de Broglie wavelength of the electron in that orbit is:

Structure of Atom

Solution:

$2 \pi r_{n}=n \lambda$
$\Rightarrow \lambda=\frac{2 \pi r_{n}}{n}=\frac{2 \times 3.14 \times 0.864}{4} nm $
$=1.3565 \,nm$