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Q. The radius of the $2^{\text {nd }}$ orbit of $Li ^{2+}$ is $x$. The expected radius of the $3^{\text {rd }}$ orbit of $Be ^{3+}$ is

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Solution:

$Li ^{2+}$
$r_2= x = k \times \frac{2^2}{3}=\frac{4 k }{2}$
$ Be ^{3+}$
$ r _3= y = k \times \frac{3^2}{4}$
$ \frac{y}{x}=\frac{9}{4} \times \frac{3}{4}=\frac{27}{16} $
$ y=\frac{27}{16} x$