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  4. The radius of the 2 He 4 nucleus is 3 fermi. The radius of 82 Pb 206 nucleus will be

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Q. The radius of the $2 He ^{4}$ nucleus is 3 fermi. The radius of ${ }_{82} Pb ^{206}$ nucleus will be

NTA AbhyasNTA Abhyas 2020Atoms

Solution:

We have, $r \propto A^{1 / 3}$ $\Rightarrow \quad \quad \frac{r_{2}}{r_{1}}=\left[\frac{A_{2}}{A_{1}}\right]^{1 / 3}=\left[\frac{206}{4}\right]^{1 / 3}$ $\therefore \quad r _{2}=3\left[\frac{206}{4}\right]^{1 / 3}=11.16$ fermi