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Physics
The radius of sphere is measured to be (2.1 ± 0.5) cm. Calculate its surface area with error limits:
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Q. The radius of sphere is measured to be $ (2.1\,\pm \,0.5)\,cm. $ Calculate its surface area with error limits:
Jharkhand CECE
Jharkhand CECE 2005
Physical World, Units and Measurements
A
$(55.4 \pm 26.4) cm ^{2}$
39%
B
$(55.4 \pm 0.02) cm ^{2}$
22%
C
$(55.4 \pm 2.64) cm ^{2}$
29%
D
$(55.4 \pm 0.26) cm ^{2}$
9%
Solution:
Surface area,
$S=4 \pi r^{2}=4 \times \frac{22}{7} \times(2.1)^{2}$
$=55.44=55.4\, cm ^{2}$
Further, $\frac{\Delta S}{S}=2 . \frac{\Delta r}{r}$
or $\Delta S=2\left(\frac{\Delta r}{r}\right)(S)$
$=\frac{2 \times 0.5 \times 55.4}{2.1}$
$=26.38=26.4 \,cm ^{2} $
$\therefore S=(55.4 \pm 26.4) cm ^{2}$