Question

The radius of nucleus of silver (atomic number $=47$ ) is $3.4 \times 10^{-14} m .$ The electric potential on the surface of nucleus is $\left(e=1.6 \times 10^{-19} C \right)$

• A. $1.99 \times 10^{6}$ volt
• B. $2.9 \times 10^{6}$ volt
• C. $4.99 \times 10^{6}$ volt
• D. $0.99 \times 10^{6}$ volt

Answer 1

Answer: (A)

$V=\frac{1}{4 \pi \varepsilon_{0}} \cdot \frac{(Z e)}{r}$
$=9 \times 10^{9} \times \frac{47 \times 1.6 \times 10^{-19}}{3.4 \times 10^{-14}}$
$=1.99 \times 10^{6} V$