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Q. The radius of $La^{3+}$ (Atomic number of $La = 57$ ) is $1.06\mathring{A}$. Which one of the following given values will be closest to the radius of $Lu^{3+}$ (Atomic number of $Lu = 71$) ?

VITEEEVITEEE 2018

Solution:

Ionic radii $\propto \frac{1}{z}$
Thus, $\frac{z_{2}}{z_{1}} \Rightarrow \frac{1.06}{\left(\text{Ionic radii of } Lu^{3+}\right)} = \frac{71}{57}$
$\Rightarrow $ Ionic radii of $Lu^{3+} = 0.85\,\mathring{A}$