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  4. The radius of circular path of an electron when subjected to a perpendicular magnetic field, will be

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Q. The radius of circular path of an electron when subjected to a perpendicular magnetic field, will be

Punjab PMETPunjab PMET 1999

Solution:

Centripetal force on the electron $ =\frac{m{{v}^{2}}}{r} $ Force on moving charge in the magnetic field is $ =Bev $ Hence $ \frac{m{{v}^{2}}}{r}=Bev $ or $ r=\frac{mv}{Be} $