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Q. The radius of an electron in second stationary orbit in Bohr's atom is $R$ . The radius of the third orbit will be

NTA AbhyasNTA Abhyas 2020Atoms

Solution:

$r=0.529\frac{n^{2}}{Z}$
$R=\frac{0.529 \times 4}{Z}$
$R^{′}=\frac{0.529 \times 9}{Z}$
$\frac{R ′}{R}=\frac{9}{4}$