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Q. The radius of $Ag^+$ ion is $126$ pm and that of $I^-$ ion is $216$ pm. The coordination number of $Ag^+$ ion is

The Solid State

Solution:

$\frac{r_{+}}{r_{-}} = \frac{126}{216} = 0.58$,
octahedral voids. Hence $C.N. = 6$.