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  4. The radius of a thin wire is 0.16 mm. The area of cross-section of wire in mm2 with correct number of significant figures is

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Q. The radius of a thin wire is 0.16 mm. The area of cross-section of wire in $mm^2$ with correct number of significant figures is

JIPMERJIPMER 2013Physical World, Units and Measurements

Solution:

Here, $R$ = 0.16 mm
Hence, $A = \pi R^2$
$ = \frac{22}{7} \times (0.16)^2 = 0.080457 \, mm^2$
Since radius has two significant figures so area also will have two significant figures.
$ \therefore \:\:\:\: A = 0.080\, mm^2$