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Q. The radioactive decay of thorium $ (A=232,\,Z=90)$ releases six alpha and four beta particles. The atomic number and mass number of the final product is

J & K CETJ & K CET 2013Nuclei

Solution:

Decrease in mass number due to
$6 \alpha=6 \times 4=24$
Decrease in change number due to
$6 \alpha=6 \times 2=12$
Increase in change number due to four $\beta=4$
$\therefore $ Net mass number $=232-24=208$
Net atomic number $=90-12+4=82$