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  4. The r. m. s. value of potential difference V shown in the figure is

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Q. The r. m. s. value of potential difference $V$ shown in the figure isPhysics Question Image

BITSATBITSAT 2012

Solution:

$V_{rms} = \sqrt{\frac{\left(T/2\right)V_{0}^{2} + 0}{T}} = \frac{V_{0}}{\sqrt{2}} .$