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Q. The quantity $X = \frac{\varepsilon _{0} L V}{t}$ where $\varepsilon _{0}$ is the permittivity of free space, $L$ is length, $V$ is the potential difference and $t$ is time. The dimensions of $X$ are the same as that of

NTA AbhyasNTA Abhyas 2022

Solution:

$[ \varepsilon _{0} L ] = [C]$
$\therefore X = \frac{\varepsilon _{0} L V}{t} = \frac{C \times V}{t} = \frac{Q}{t}$ = current