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Q. The quantity of charge required to obtain one mole of aluminium from $Al_2O_3$ is________.

Electrochemistry

Solution:

$Al_{2}O_{3} \to2Al$
$2Al^{3+}+6e^{-} \to2Al$
$\therefore Al^{3+}+3e^{-} \to Al$
Thus, $3 \,F$ of charge is required to obtain $1 \,mole$ of $Al$ from $Al_2O_3$.