Question

The quantity of a charge that will be transferred by a current flow of $20 \, A$ over $1 \, h \, 30 \, min$ period is

• A. $10.8\times 10^{3 \, }C$
• B. $10.8\times 10^{4 \, }C$
• C. $5.4\times 10^{3 \, }C$
• D. $1.8\times 10^{4 \, }C$

Answer 1

Answer: (B)

Electric current, $I=\frac{d Q}{d t}$
$dQ=Idt$
$t_{1}=0,t_{2}=1 \, h \, 30 \, min$
$=90min \, =90\times 60=5400 \, s$
Electric charge, $Q = I . t$
$= 20 \times 5400 \, C$
$= 10.8 \times 10^{4 \, } C$