Q. The propositions $ \left(p \Rightarrow p\right) \wedge \left(\sim p \Rightarrow p\right) $ is a
MHT CETMHT CET 2011
Solution:
p
$\sim p$
$p \Rightarrow \sim p$
$\sim p \Rightarrow p $
$(p \Rightarrow \sim p) \wedge(\sim p \Rightarrow p)$
T
F
F
T
F
F
T
T
F
F
Clearly, $(p\Rightarrow \sim p) \wedge(\sim p \Rightarrow p)$ is a contradiction.
| p | $\sim p$ | $p \Rightarrow \sim p$ | $\sim p \Rightarrow p $ | $(p \Rightarrow \sim p) \wedge(\sim p \Rightarrow p)$ |
| T | F | F | T | F |
| F | T | T | F | F |