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Q. The products of the fission of $U^{235}$ by thermal neutron are

Nuclei

Solution:

$U^{235} \to {}_{56}^{144}Ba + {}_{36}^{89} Kr + 3 {}_{b}^{1}n$
$U^{235} + {}_{0}^{1} n \to U^{236} \to {}_{51}^{183}Sb + {}_{41}^{99}Nb + 4{}_{0}^{1}n$