Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The products obtained during treatment of hard water using Clark's method are:
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. The products obtained during treatment of hard water using Clark's method are:
JEE Main
JEE Main 2022
The s-Block Elements
A
$CaCO _3$ and $MgCO _3$
B
$Ca ( OH )_2$ and $Mg ( OH )_2$
C
$CaCO _3$ and $Mg ( OH )_2$
D
$Ca ( OH )_2$ and $MgCO _3$
Solution:
Sol. In Clark's method lime water is used
$Ca \left( HCO _3\right)_2+2 Ca ( OH )_2 \rightarrow 2 CaCO _3+2 H _2 O $
$ Mg \left( HCO _3\right)_2+2 Ca ( OH )_2 \rightarrow 2 CaCO _3+ Mg ( OH )_2+2 H _2 O$